Thread: "2x2x2x2x2 (5D cube)"

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I was thinking on 2^5...This cube is simply 10 x mono colourfull hypercubes=
2^4 . Okey ! Not so simply ;D!

to SEE its comlpexity I made some pictures (I know it's not perfect...but I=
had to see these 10 hypercubes in one place!:). I did it using paint from =
windows (I've instaled Corel today in which I did some arrows on one of jpe=
gs):

Look on the Photo Area ( there should be some pictures of 2x2x2x2x2). I mad=
e also temporary gallery on:=20

http://genezis.station76.pl/Science/5D/index.html


Melinda wrote:

Of course it is not a=20
> single projection. I could imagine that it could be a view of a possible=
=20
> user interface for this monster=20

It's exactly what I was thinkig about...(I suppose programing is not the pr=
oblem but interface...)
(by the way how does the twist is described (in mathematical way) in the pr=
ogram?)


but I don't think you could generate any smooth twists with it.=20

You're right. I tried to imagine single twist ...and i must say it's real S=
OMETHING ;)

That is, I think that when you perform a twist,=20
> the resulting state would have colored slices jumping into seemingly=20
> random positions even when you twist on the middle gray 2^4.

I see it too...The complicated dance around the whole 5D cube... :)=20

but I haven't lost my hope because I know...that I can't even handle 2^4!!!=
(I can't see everything...what going on the whole cube after 2 twists, etc=
) and still I can solve it...I make new algoritms...etc...

Algoritms are the key...You don't have to handle everything if you have seq=
uence to change 2 pieces...(You just move pieces where you want, make seque=
nce and return them...(You see only a little part of system...and you are n=
ot afraid of the compexity of the whole picture)

(5^4 is unbeliveble! to solve, look on number of pieces and how everythin=
g is mixing (on surface and inside) but still 3 men managed to solve this..=
.

I think the same will be with 2^5...



I can't=20
> even imagine solving a 3D cube unfolded in the same way onto 2D, so a 5D=
=20
> cube? Well, I'm not sure anybody could do it.=20

(there are some who will try...for example ME :P)
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