Thread: "2x2x2x2x2 (5D cube)"

From: "Remigiusz Durka" <thesamer@interia.pl>
Date: Sat, 11 Mar 2006 18:53:35 +0100
Subject: 2x2x2x2x2 (5D cube)



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I was thinking on 2^5...This cube is simply 10 x mono colourfull hypercubes=
2^4 . Okey ! Not so simply ;D!

to SEE its comlpexity I made some pictures (I know it's not perfect...but I=
had to see these 10 hypercubes in one place!:). I did it using paint from =
windows (I've instaled Corel today in which I did some arrows on one of jpe=
gs):

Look on the Photo Area ( there should be some pictures of 2x2x2x2x2). I mad=
e also temporary gallery on:=20

http://genezis.station76.pl/Science/5D/index.html


Melinda wrote:

Of course it is not a=20
> single projection. I could imagine that it could be a view of a possible=
=20
> user interface for this monster=20

It's exactly what I was thinkig about...(I suppose programing is not the pr=
oblem but interface...)
(by the way how does the twist is described (in mathematical way) in the pr=
ogram?)


but I don't think you could generate any smooth twists with it.=20

You're right. I tried to imagine single twist ...and i must say it's real S=
OMETHING ;)

That is, I think that when you perform a twist,=20
> the resulting state would have colored slices jumping into seemingly=20
> random positions even when you twist on the middle gray 2^4.

I see it too...The complicated dance around the whole 5D cube... :)=20

but I haven't lost my hope because I know...that I can't even handle 2^4!!!=
(I can't see everything...what going on the whole cube after 2 twists, etc=
) and still I can solve it...I make new algoritms...etc...

Algoritms are the key...You don't have to handle everything if you have seq=
uence to change 2 pieces...(You just move pieces where you want, make seque=
nce and return them...(You see only a little part of system...and you are n=
ot afraid of the compexity of the whole picture)

(5^4 is unbeliveble! to solve, look on number of pieces and how everythin=
g is mixing (on surface and inside) but still 3 men managed to solve this..=
.

I think the same will be with 2^5...



I can't=20
> even imagine solving a 3D cube unfolded in the same way onto 2D, so a 5D=
=20
> cube? Well, I'm not sure anybody could do it.=20

(there are some who will try...for example ME :P)
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>




 

I was thinking on 2=
^5...This=20
cube is simply 10 x mono colourfull hypercubes 2^4 . Okey ! Not so simply=20
;D!

 

to SEE its comlpexity I =
made=20
some pictures (I know it's not perfect...but I had to see these 10=20
hypercubes in one place!:). I did it using pain=
t from=20
windows (I've instaled Corel today in which I did some arrows on =
one=20
of jpegs):

 

Look on the Photo Area ( ther=
e should be=20
some pictures of 2x2x2x2x2). I made also temporary gallery on:=20

 

size=3D2>http://genezis.station76.pl/Science/5D/index.html

 

 

Melinda=20
wrote:

 

Of course it is n=
ot a=20

> single projection. I could imagine that it could be a view of a=20
possible
> user interface for this monster
V>
 

It's exactly what I was think=
ig=20
about...(I suppose programing is not the problem but interface...)
DIV>
(by the way how does the=
twist is=20
described (in mathematical way) in the program?)

 

 

but I don't think=
you could=20
generate any  smooth twists with it.

 

You're right. I tried to imag=
ine single=20
twist ...and i must say it's real SOMETHING ;)

 

That is, I think =
that when=20
you perform a twist,
> the resulting state would have colored slices=
=20
jumping into seemingly
> random positions even when you twist on the=
=20
middle gray 2^4.

 

I see it too...The complicate=
d dance=20
around the whole 5D cube... :)

 

but I haven't lost my hope be=
cause I=20
know...that I can't even handle 2^4!!! (I can't see everything...what =
going=20
on the whole cube after 2 twists, etc) and still I can solve it...I make ne=
w=20
algoritms...etc...

 

Algoritms are the key...You d=
on't have=20
to handle everything if you have sequence to change 2 pieces...(You just mo=
ve=20
pieces where you want, make sequence and return them...(You see only a litt=
le=20
part of system...and you are not afraid of the compexity of the whole=20
picture)

 

(5^4  is unbelivebl=
e! to=20
solve, look on number of pieces  and how everything is mixing (on surf=
ace=20
and inside) but still 3 men managed to solve this...

 

I think the same will be with=
=20
2^5...

 

 

 

 I can't >> even=20
imagine solving a 3D cube unfolded in the same way onto 2D, so a 5D
>=
;=20
cube? Well, I'm not sure anybody could do it.

 

(there are some who will try.=
..for=20
example ME :P)



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