Thread: "The 2c piece"
From: alvin5553@gmail.com
Date: 22 Jan 2015 19:00:10 -0800
Subject: The 2c piece
From: alvin5553@gmail.com
Date: Fri, 23 Jan 2015 19:47:13 -0800
Subject: The 2c piece
--------------070602060905000808070703
Content-Type: text/plain; charset=utf-8; format=flowed
Content-Transfer-Encoding: quoted-printable
Hello Alvin,
First, there are no 5-color pieces in 4D; only 1C through 4C. The 1C=20
pieces are the ones at the very center of the faces, and do not have=20
neighbors by definition. They cannot be twisted, but they do rotate in=20
place whenever you twist about any other pieces. The way to think about=20
all twists is that you highlight any non-central sticker on a face, and=20
imagine a ray that starts from the center sticker of that face and=20
passes through the highlighted sticker. This defines the axis that will=20
be twisted about if you click left or right.
I hope that helps,
-Melinda
On 1/22/2015 7:00 PM, alvin5553@gmail.com [4D_Cubing] wrote:
>
>
> So when you turn of the 3c, 4c, and 5c pieces, you have this center=20
> section where it's full of stickers. I've found out that the outermost=20
> sticker of that center section and the innermost sticker are the same=20
> piece, but I can't turn that piece. If you count from the outermost=20
> sticker and go inside, the sixth sticker is the innermost 2c piece=20
> that can be turned. so how am I suppose to solve that piece?
>
>
>
>
>=20
--------------070602060905000808070703
Content-Type: text/html; charset=utf-8
Content-Transfer-Encoding: quoted-printable
">
Hello Alvin,
First, there are no 5-color pieces in 4D; only 1C through 4C. The 1C
pieces are the ones at the very center of the faces, and do not have
neighbors by definition. They cannot be twisted, but they do rotate
in place whenever you twist about any other pieces. The way to think
about all twists is that you highlight any non-central sticker on a
face, and imagine a ray that starts from the center sticker of that
face and passes through the highlighted sticker. This defines the
axis that will be twisted about if you click left or right.
I hope that helps,
-Melinda
sans-serif;font-size:13px;line-height:normal;">So when you
turn of the 3c, 4c, and 5c pieces, you have this center
section where it's full of stickers. I've found out that the
outermost sticker of that center section and the innermost
sticker are the same piece, but I can't turn that piece. If
you count from the outermost sticker and go inside, the
sixth sticker is the innermost 2c piece that can be turned.
so how am I suppose to solve that piece? class=3D"yui-cursor">
=20=20=20=20=20=20
--------------070602060905000808070703--
From: "NDCuber ." <alvin5553@gmail.com>
Date: Fri, 23 Jan 2015 19:54:31 -0800
Subject: Re: [MC4D] The 2c piece
From: "NDCuber ." <alvin5553@gmail.com>
Date: Fri, 23 Jan 2015 22:38:44 -0800
Subject: Re: [MC4D] The 2c piece
--------------010004090305010107040100
Content-Type: text/plain; charset=utf-8; format=flowed
Content-Transfer-Encoding: quoted-printable
Yes, well that is a rather important detail! :-)
Hopefully Roice or another 5D solver will answer.
On 1/23/2015 7:54 PM, 'NDCuber .' alvin5553@gmail.com [4D_Cubing] wrote:
>
>
> oh, I forgot to mention that I was talking about the 5D Cube...
>
> On Fri, Jan 23, 2015 at 7:47 PM, Melinda Green=20
> melinda@superliminal.com [4D_Cubing]=20
> <4D_Cubing@yahoogroups.com > wrote:
>
> Hello Alvin,
>
> First, there are no 5-color pieces in 4D; only 1C through 4C. The
> 1C pieces are the ones at the very center of the faces, and do not
> have neighbors by definition. They cannot be twisted, but they do
> rotate in place whenever you twist about any other pieces. The way
> to think about all twists is that you highlight any non-central
> sticker on a face, and imagine a ray that starts from the center
> sticker of that face and passes through the highlighted sticker.
> This defines the axis that will be twisted about if you click left
> or right.
>
> I hope that helps,
> -Melinda
>
> On 1/22/2015 7:00 PM, alvin5553@gmail.com
> [4D_Cubing] wrote:
>>
>> So when you turn of the 3c, 4c, and 5c pieces, you have this
>> center section where it's full of stickers. I've found out that
>> the outermost sticker of that center section and the innermost
>> sticker are the same piece, but I can't turn that piece. If you
>> count from the outermost sticker and go inside, the sixth sticker
>> is the innermost 2c piece that can be turned. so how am I suppose
>> to solve that piece?
>>
>>
>
>
>
>
>=20
--------------010004090305010107040100
Content-Type: text/html; charset=utf-8
Content-Transfer-Encoding: quoted-printable
">
Yes, well that is a rather important detail! :-)
Hopefully Roice or another 5D solver will answer.
cite=3D"mid:CAHH4SSU4_eS78JHfD63O2NcNs1LJtEOCpvv1uU0f4aK5MxhUAw@mail.gmail.=
com"
type=3D"cite">
oh, I forgot to mention that I was talking about
the 5D Cube...
=20=20=20=20=20=20
--------------010004090305010107040100--
From: Roice Nelson <roice3@gmail.com>
Date: Tue, 27 Jan 2015 18:24:44 -0600
Subject: Re: [MC4D] The 2c piece
--001a11c36de8f06b30050dab652a
Content-Type: text/plain; charset=UTF-8
Content-Transfer-Encoding: quoted-printable
Hi Alvin,
My apologies for the delay. Those central stickers are definitely hard to
work with! You get 3 stickers that project to the origin from 4 faces (+-U
and +-V), so 12 stickers are all mashed on top of each other when all the
faces are visible. Some of these are 1C stickers and some of them are 2C
stickers. The locations depend on your projection and visibility settings.
There are two ways I know of to deal with solving the centrally projected
stickers.
(1) Do a View Rotation using the buttons at the bottom right to move the
central stickers out to the side, then work with them there.
(2) After starting a twist, the arrow keys allow you to cycle through
2nd-click stickers. This feature can give you some choice between the two
centrally projected stickers.
I recommend (1) myself. Also, I've had reports that the feature in (2) is
no longer be working correctly on some systems. If this is true for you,
you'll be stuck with using view rotations for now.
Good luck!
Roice
On Thu, Jan 22, 2015 at 9:00 PM, alvin5553@gmail.com [4D_Cubing] <
4D_Cubing@yahoogroups.com> wrote:
>
>
> So when you turn of the 3c, 4c, and 5c pieces, you have this center
> section where it's full of stickers. I've found out that the outermost
> sticker of that center section and the innermost sticker are the same
> piece, but I can't turn that piece. If you count from the outermost stick=
er
> and go inside, the sixth sticker is the innermost 2c piece that can be
> turned. so how am I suppose to solve that piece?
>
>
>
>
>=20
>
--001a11c36de8f06b30050dab652a
Content-Type: text/html; charset=UTF-8
Content-Transfer-Encoding: quoted-printable
Hi Alvin,
My apologies for the delay.=
=C2=A0 Those central stickers are definitely hard to work with!=C2=A0 You g=
et 3 stickers that project to the origin from 4 faces (+-U and +-V), so 12 =
stickers are all mashed on top of each other when all the faces are visible=
.=C2=A0 Some of these are 1C stickers and some of them are 2C stickers.=C2=
=A0 The locations depend on your projection and visibility settings.
<=
div>
There are two ways I know of to deal with solving the ce=
ntrally projected stickers.
(1) Do a View Rotation=
using the buttons at the bottom right to move the central stickers out to =
the side, then work with them there.
(2) After starting a twist, =
the arrow keys allow you to cycle through 2nd-click stickers.=C2=A0 This fe=
ature can give you some choice between the two centrally projected stickers=
.
I recommend (1) myself.=C2=A0 Also, I've had=
reports that the feature in (2) is no longer be working correctly on some =
systems.=C2=A0 If this is true for you, you'll be stuck with using view=
rotations for now.
Good luck!
Roicev>
--001a11c36de8f06b30050dab652a--