Thread: "Need Help on the 3x3x3x3x3"

From: alvin5553@gmail.com
Date: 25 Dec 2014 07:52:25 -0800
Subject: Need Help on the 3x3x3x3x3




From: alvin5553@gmail.com
Date: 25 Dec 2014 10:35:56 -0800
Subject: Need Help on the 3x3x3x3x3




From: deust.secard94@yahoo.ca
Date: Thu, 25 Dec 2014 15:29:30 -0800
Subject: Re: Need Help on the 3x3x3x3x3



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Thank you for calculating the permutations, Andrey. That's the largest=20
number of positions I recall seeing for any twisty puzzle. It's so large=20
that I really don't know how to get my head around it.

What is the largest puzzle that has been solved? I have lost track. Will=20
anyone ever solve the 5^7? I don't know but I've learned never to bet=20
against the determination of twisty puzzle enthusiasts!

I'd also like to note that the 8^4 has recently been solved. His name=20
is David Cohoe, and he declined to join the group and announce it for=20
himself, so I want to call out his very impressive accomplishment.=20
Congratulations David!

-Melinda

On 12/25/2014 5:17 AM, andreyastrelin@yahoo.com [4D_Cubing] wrote:
>
>
> ... is the number of different positions of 5^7 cube. This cube has 28=20
> different kinds of pieces. Pieces of 8 kinds have unique positions in=20
> the solved cube, and pieces from other 20 kinds can be swapped when=20
> they belong to the same face (that may have from 2 to 6 dimensions). 6=20
> groups (1C pieces) have no additional constraints, and other 14 have=20
> one constraint (parity of total orientation of pieces). Only=20
> constraint for side 6C pieces and for 7C is the parity of=20
> permutations, central 2C have constraint for orientations, and 4 other=20
> groups (central 3C,4C,5C and 6C) have both constraints.
>
> Merry Christmas!
>
>
>
>=20


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">


Thank you for calculating the permutations, Andrey. That's the
largest number of positions I recall seeing for any twisty puzzle.
It's so large that I really don't know how to get my head around it.




What is the largest puzzle that has been solved? I have lost track.
Will anyone ever solve the 5^7? I don't know but I've learned never
to bet against the determination of twisty puzzle enthusiasts!



I'd also like to note that the=C2=A0 8^4 has recently been solved. His
name is David Cohoe, and he declined to join the group and announce
it for himself, so I want to call out his very impressive
accomplishment. Congratulations David!



-Melinda



On 12/25/2014 5:17 AM,
ahoo.com">andreyastrelin@yahoo.com [4D_Cubing] wrote:





... is the number of different positions of 5^7 cube.
This cube has 28 different kinds of pieces. Pieces of 8 kinds
have unique positions in the solved cube, and pieces from
other 20 kinds can be swapped when they belong to the same
face (that may have from 2 to 6 dimensions). 6 groups (1C
pieces) have no additional constraints, and other 14 have one
constraint (parity of total orientation of pieces). Only
constraint for side 6C pieces and for 7C=C2=A0is the parity of
permutations, central 2C have constraint for orientations, and
4 other groups (central 3C,4C,5C and 6C) have both
constraints.


=C2=A0 Merry Christmas!


=20=20=20=20=20=20







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