Thread: "MagicTile Solving intermediate report"

From: "Eduard" <baumann@mcnet.ch>
Date: Mon, 03 Dec 2012 14:29:51 -0000
Subject: MagicTile Solving intermediate report



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MT_ell_sph_dode_E_0-1-0,11 part 2
b.PNG>

After succeeding with the cornerfaces I'm left with a single corner swap
!! I have macros to manage the edgefaces, small faces and central faces,
which do not touch the corners. How can I solve this parity problem ?
Because a belt of 10 corners is even I can go from 2134567890 to
0987654321with 3-cycles (even number of swaps; pay attention to the
reversed 21 in startposition). Then I have to swap the upper and lower
ring of 5 corners (5 swaps, odd). Then change direction in each 5-ring
(even number of swaps). Total : odd number of swaps which is not
possible with 3-cycles.
I don't see a solution for the moment.
Who can help me?


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_0-1-0,11_b.PNG">MT_ell_sph_dode_E_0-1-0,11 part 2 


After succeeding with the cornerfaces I'm left with a single corner s=
wap
!! I have macros to manage the edgefaces, small faces and central f=
aces, which do not touch the corners. How can I solve this parity problem ?=

Because a belt of 10 corners is even I can go from 2134567890 to 09876=
54321with 3-cycles (even number of swaps; pay attention to the reversed 21 =
in startposition). Then I have to swap the upper and lower ring of 5 corner=
s (5 swaps, odd). Then change direction in each 5-ring (even number of swap=
s). Total : odd number of swaps which is not possible with 3-cycles.
I d=
on't see a solution for the moment.
Who can help me?



--1-8539781028-7649429877=:8--




From: "schuma" <mananself@gmail.com>
Date: Mon, 03 Dec 2012 16:20:40 -0000
Subject: Re: MagicTile Solving intermediate report



Ed,

You need to first swap the two incorrect 3c corners to fix them. Then you n=
eed to do two swaps for triangles in two orbits. Although you cannot do one=
swap in a single orbit, it turns out you can do two of them simultaneously=
: Let A and B be two adjacent edges sharing one vertex. (A,B)*3 does the jo=
bs. Please examine which two orbits this algorithm affects and apply it in =
the correct spot. Then you can use your old algorithms to do even permutati=
ons within orbits.=20

Nan

--- In 4D_Cubing@yahoogroups.com, "Eduard" wrote:
>
>=20
> MT_ell_sph_dode_E_0-1-0,11 part 2
> > b.PNG>
>=20
> After succeeding with the cornerfaces I'm left with a single corner swap
> !! I have macros to manage the edgefaces, small faces and central faces,
> which do not touch the corners. How can I solve this parity problem ?
> Because a belt of 10 corners is even I can go from 2134567890 to
> 0987654321with 3-cycles (even number of swaps; pay attention to the
> reversed 21 in startposition). Then I have to swap the upper and lower
> ring of 5 corners (5 swaps, odd). Then change direction in each 5-ring
> (even number of swaps). Total : odd number of swaps which is not
> possible with 3-cycles.
> I don't see a solution for the moment.
> Who can help me?
>




From: "Eduard Baumann" <baumann@mcnet.ch>
Date: Mon, 3 Dec 2012 19:59:22 +0100
Subject: Re: [MC4D] Re: MagicTile Solving intermediate report



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Okay.
Thanks.
I will try.
Kind regards
Ed

----- Original Message -----=20
From: schuma=20
To: 4D_Cubing@yahoogroups.com=20
Sent: Monday, December 03, 2012 5:20 PM
Subject: [MC4D] Re: MagicTile Solving intermediate report


=20=20=20=20
Ed,

You need to first swap the two incorrect 3c corners to fix them. Then you=
need to do two swaps for triangles in two orbits. Although you cannot do o=
ne swap in a single orbit, it turns out you can do two of them simultaneous=
ly: Let A and B be two adjacent edges sharing one vertex. (A,B)*3 does the =
jobs. Please examine which two orbits this algorithm affects and apply it i=
n the correct spot. Then you can use your old algorithms to do even permuta=
tions within orbits.=20

Nan

--- In 4D_Cubing@yahoogroups.com, "Eduard" wrote:
>
>=20
> MT_ell_sph_dode_E_0-1-0,11 part 2
> _\
> b.PNG>
>=20
> After succeeding with the cornerfaces I'm left with a single corner swa=
p
> !! I have macros to manage the edgefaces, small faces and central faces=
,
> which do not touch the corners. How can I solve this parity problem ?
> Because a belt of 10 corners is even I can go from 2134567890 to
> 0987654321with 3-cycles (even number of swaps; pay attention to the
> reversed 21 in startposition). Then I have to swap the upper and lower
> ring of 5 corners (5 swaps, odd). Then change direction in each 5-ring
> (even number of swaps). Total : odd number of swaps which is not
> possible with 3-cycles.
> I don't see a solution for the moment.
> Who can help me?
>



=20=20
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>


Okay.

Thanks.

I will try.

Kind regards

Ed

 

style=3D"BORDER-LEFT: #000000 2px solid; PADDING-LEFT: 5px; PADDING-RIGHT: =
0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px">
----- Original Message -----

style=3D"FONT: 10pt arial; BACKGROUND: #e4e4e4; font-color: black">Fro=
m:
=20
schuma=
=20

To: ps.com=20
href=3D"mailto:4D_Cubing@yahoogroups.com">4D_Cubing@yahoogroups.com
<=
/DIV>
Sent: Monday, December 03, 2012 5:=
20=20
PM

Subject: [MC4D] Re: MagicTile Solv=
ing=20
intermediate report


 =20

Ed,

You need to first swap the two incorrect 3c corners to fix =
them.=20
Then you need to do two swaps for triangles in two orbits. Although you c=
annot=20
do one swap in a single orbit, it turns out you can do two of them=20
simultaneously: Let A and B be two adjacent edges sharing one vertex. (A,=
B)*3=20
does the jobs. Please examine which two orbits this algorithm affects and=
=20
apply it in the correct spot. Then you can use your old algorithms to do =
even=20
permutations within orbits.

Nan

--- In href=3D"mailto:4D_Cubing%40yahoogroups.com">4D_Cubing@yahoogroups.com=
,=20
"Eduard" <baumann@...> wrote:
>
>
>=20
MT_ell_sph_dode_E_0-1-0,11 part 2
> < href=3D"http://wiki.superliminal.com/wiki/File:Pict_MT_ell_sph_dode_E_0-1=
-0,11_">http://wiki.superliminal.com/wiki/File:Pict_MT_ell_sph_dode_E_0-1-0=
,11_\
>=20
b.PNG>
>
> After succeeding with the cornerfaces I'm left=
with=20
a single corner swap
> !! I have macros to manage the edgefaces, sm=
all=20
faces and central faces,
> which do not touch the corners. How can =
I=20
solve this parity problem ?
> Because a belt of 10 corners is even =
I can=20
go from 2134567890 to
> 0987654321with 3-cycles (even number of swa=
ps;=20
pay attention to the
> reversed 21 in startposition). Then I have t=
o=20
swap the upper and lower
> ring of 5 corners (5 swaps, odd). Then c=
hange=20
direction in each 5-ring
> (even number of swaps). Total : odd numb=
er of=20
swaps which is not
> possible with 3-cycles.
> I don't see a=
=20
solution for the moment.
> Who can help me?
>

V>

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