Thread: "flaw in 4 color theorem "proof""

From: "Eduard" <baumann@mcnet.ch>
Date: Sat, 10 Nov 2012 22:13:42 -0000
Subject: flaw in 4 color theorem "proof"



Please tell me the flaw in 4 color theorem "proof" http://www.superliminal.=
com/4color/4color.htm




From: "Eduard" <baumann@mcnet.ch>
Date: Sat, 10 Nov 2012 14:57:58 -0800
Subject: flaw in 4 color theorem "proof"



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On 11/10/2012 2:13 PM, Eduard wrote:
> Please tell me the flaw in 4 color theorem "proof" http://www.superliminal.com/4color/4color.htm

Hello Eduard,

I'm really happy that you worked on this puzzle. It may be the hardest
and most beautiful math problem that I know of and only two people have
found the flaw in our treatment in the 18 years or so since we published
it. I'll make readers scroll way down to read it for those who want to
take a stab at it before reading the answer.
.
.
.





























































All of the logic in the text is correct up to the penultimate step. The
flaw is that steps 14 and 15 are mutually exclusive. You can perform
either one of them just fine but you can't do the second one after doing
the first because the first color swapping might affect the other, and
that subtle fact kills the proof. The reason the loops can affect each
other is because both loops contain green regions. That allows one chain
pass through the other chain's loop and have its other color changed,
destroying the chain. It's natural to want to say "Well that's an
extremely unlikely thing to happen in a random map", but that's what
happens in math. It needs to 100% correct or it doesn't count.

In my opinion this is a crying shame because the basic idea and the
logical flow are truly beautiful and elegant. It was discovered by Kempe
which is why the loops are called "Kempe chains". It was widely accepted
until the flaw shattered it. From Wikipedia:

/In 1879 Kempe wrote his famous "proof" of the //four color theorem
//, shown incorrect
by //Percy Heawood //in
1890. Much later, his work led to fundamental concepts such as the
//Kempe chain //and
unavoidable sets.//
/

Kempe (I think) was able to use it to prove that all maps can be colored
with at most 5 colors, so at least something good came of it. You can
now understand why adding a fifth color works. You simply use the extra
color to replace all the green regions in one of the two loops. That way
they can't intersect and the proof holds. Pretty neat, don't you think?

-Melinda

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Content-Type: text/html; charset=ISO-8859-1
Content-Transfer-Encoding: 7bit



http-equiv="Content-Type">


On 11/10/2012 2:13 PM, Eduard wrote:


Please tell me the flaw in 4 color theorem "proof" http://www.superliminal.com/4color/4color.htm




Hello Eduard,



I'm really happy that you worked on this puzzle. It may be the
hardest and most beautiful math problem that I know of and only two
people have found the flaw in our treatment in the 18 years or so
since we published it. I'll make readers scroll way down to read it
for those who want to take a stab at it before reading the answer.

.

.

.



























































































































All of the logic in the text is correct up to the penultimate step.
The flaw is that steps 14 and 15 are mutually exclusive. You can
perform either one of them just fine but you can't do the second one
after doing the first because the first color swapping might affect
the other, and that subtle fact kills the proof. The reason the
loops can affect each other is because both loops contain green
regions. That allows one chain pass through the other chain's loop
and have its other color changed, destroying the chain. It's natural
to want to say "Well that's an extremely unlikely thing to happen in
a random map", but that's what happens in math. It needs to 100%
correct or it doesn't count.



In my opinion this is a crying shame because the basic idea and the
logical flow are truly beautiful and elegant. It was discovered by
Kempe which is why the loops are called "Kempe chains". It was
widely accepted until the flaw shattered it. From Wikipedia:

In 1879 Kempe wrote his famous "proof" of the href="http://en.wikipedia.org/wiki/Four_color_theorem"
title="Four color theorem">four color theorem
,
shown incorrect by
href="http://en.wikipedia.org/wiki/Percy_Heawood" title="Percy
Heawood" class="mw-redirect">Percy Heawood
in 1890.
Much later, his work led to fundamental concepts such as the
href="http://en.wikipedia.org/wiki/Kempe_chain" title="Kempe
chain">Kempe chain
and unavoidable sets.


Kempe (I think) was able to use it to prove that all maps can be
colored with at most 5 colors, so at least something good came of
it. You can now understand why adding a fifth color works. You
simply use the extra color to replace all the green regions in one
of the two loops. That way they can't intersect and the proof holds.
Pretty neat, don't you think?



-Melinda




--------------020403080902060802020006--




From: "Eduard Baumann" <baumann@mcnet.ch>
Date: Sun, 11 Nov 2012 11:39:03 +0100
Subject: Re: [MC4D] flaw in 4 color theorem "proof"



------=_NextPart_000_004D_01CDC001.268B0E00
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charset="iso-8859-1"
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Nice. Thanks very much. Ed.

----- Original Message -----=20
From: Melinda Green=20
To: 4D_Cubing@yahoogroups.com=20
Sent: Saturday, November 10, 2012 11:57 PM
Subject: Re: [MC4D] flaw in 4 color theorem "proof"


=20=20=20=20
On 11/10/2012 2:13 PM, Eduard wrote:


Please tell me the flaw in 4 color theorem "proof" http://www.superliminal.=
com/4color/4color.htm

Hello Eduard,

I'm really happy that you worked on this puzzle. It may be the hardest an=
d most beautiful math problem that I know of and only two people have found=
the flaw in our treatment in the 18 years or so since we published it. I'l=
l make readers scroll way down to read it for those who want to take a stab=
at it before reading the answer.
.
.
.





























































All of the logic in the text is correct up to the penultimate step. The f=
law is that steps 14 and 15 are mutually exclusive. You can perform either =
one of them just fine but you can't do the second one after doing the first=
because the first color swapping might affect the other, and that subtle f=
act kills the proof. The reason the loops can affect each other is because =
both loops contain green regions. That allows one chain pass through the ot=
her chain's loop and have its other color changed, destroying the chain. It=
's natural to want to say "Well that's an extremely unlikely thing to happe=
n in a random map", but that's what happens in math. It needs to 100% corre=
ct or it doesn't count.

In my opinion this is a crying shame because the basic idea and the logic=
al flow are truly beautiful and elegant. It was discovered by Kempe which i=
s why the loops are called "Kempe chains". It was widely accepted until the=
flaw shattered it. From Wikipedia:

In 1879 Kempe wrote his famous "proof" of the four color theorem, shown=
incorrect by Percy Heawood in 1890. Much later, his work led to fundamenta=
l concepts such as the Kempe chain and unavoidable sets.

Kempe (I think) was able to use it to prove that all maps can be colored =
with at most 5 colors, so at least something good came of it. You can now u=
nderstand why adding a fifth color works. You simply use the extra color to=
replace all the green regions in one of the two loops. That way they can't=
intersect and the proof holds. Pretty neat, don't you think?

-Melinda


=20=20
------=_NextPart_000_004D_01CDC001.268B0E00
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable



>


Nice. Thanks very much. Ed.

 

style=3D"BORDER-LEFT: #000000 2px solid; PADDING-LEFT: 5px; PADDING-RIGHT: =
0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px">
----- Original Message -----

style=3D"FONT: 10pt arial; BACKGROUND: #e4e4e4; font-color: black">Fro=
m:
=20
href=3D"mailto:melinda@superliminal.com">Melinda Green
To: ps.com=20
href=3D"mailto:4D_Cubing@yahoogroups.com">4D_Cubing@yahoogroups.com
<=
/DIV>
Sent: Saturday, November 10, 2012 =
11:57=20
PM

Subject: Re: [MC4D] flaw in 4 colo=
r=20
theorem "proof"


 =20

On 11/10/2012 2:13 PM, Eduard wrote:

"">Please tell me the flaw in 4 color theorem "proof" nk-freetext href=3D"http://www.superliminal.com/4color/4color.htm">http://w=
ww.superliminal.com/4color/4color.htm


Hello Eduard,

I'm really happy that you worke=
d=20
on this puzzle. It may be the hardest and most beautiful math problem tha=
t I=20
know of and only two people have found the flaw in our treatment in the 1=
8=20
years or so since we published it. I'll make readers scroll way down to r=
ead=20
it for those who want to take a stab at it before reading the=20
answer.
.
.
.











>

















R>

















<=
BR>










All=20
of the logic in the text is correct up to the penultimate step. The flaw =
is=20
that steps 14 and 15 are mutually exclusive. You can perform either one o=
f=20
them just fine but you can't do the second one after doing the first beca=
use=20
the first color swapping might affect the other, and that subtle fact kil=
ls=20
the proof. The reason the loops can affect each other is because both loo=
ps=20
contain green regions. That allows one chain pass through the other chain=
's=20
loop and have its other color changed, destroying the chain. It's natural=
to=20
want to say "Well that's an extremely unlikely thing to happen in a rando=
m=20
map", but that's what happens in math. It needs to 100% correct or it doe=
sn't=20
count.

In my opinion this is a crying shame because the basic idea=
and=20
the logical flow are truly beautiful and elegant. It was discovered by Ke=
mpe=20
which is why the loops are called "Kempe chains". It was widely accepted =
until=20
the flaw shattered it. From Wikipedia:

In 1879 Kempe wrote his famous "proof" of the title=3D"Four color theorem"=20
href=3D"http://en.wikipedia.org/wiki/Four_color_theorem">four color=20
theorem
, shown incorrect by title=3D"Percy Heawood"=20
href=3D"http://en.wikipedia.org/wiki/Percy_Heawood">Percy Heawood
I>=20
in 1890. Much later, his work led to fundamental concepts such as the=20
href=3D"http://en.wikipedia.org/wiki/Kempe_chain">Kempe chain> and=20
unavoidable sets.

Kempe (I think) was able t=
o use=20
it to prove that all maps can be colored with at most 5 colors, so at lea=
st=20
something good came of it. You can now understand why adding a fifth colo=
r=20
works. You simply use the extra color to replace all the green regions in=
one=20
of the two loops. That way they can't intersect and the proof holds. Pret=
ty=20
neat, don't you think?

-Melinda



------=_NextPart_000_004D_01CDC001.268B0E00--




From: "Andrey" <andreyastrelin@yahoo.com>
Date: Sun, 11 Nov 2012 11:07:35 -0000
Subject: Re: flaw in 4 color theorem "proof"



Hi Melinda,
I haven't read bottom of your message, but in the proof I don't like item=
s 14-15: what if blue-green chain will intersect with red-green? In that ca=
se you can't isolate both yellow areas, but I'm not sure if this case can b=
e fixed easily.

Andrey




From: "Andrey" <andreyastrelin@yahoo.com>
Date: Sun, 11 Nov 2012 18:36:04 -0800
Subject: Re: flaw in 4 color theorem "proof"



--------------000301090302010805070305
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Content-Transfer-Encoding: 7bit

Both Andrey and Norbert are correct and have now doubled the number of
solvers. Norber's was sent to me privately and included a nice
counterexample. He was surprised with the dearth of solvers, but I think
that our group is much better equipped for this sort of puzzle than the
general puzzling community. Maybe one of you who also participate in the
speedsolving forums would like to post the puzzle there and we will see
if my guess is right? I have gotten lots of wrong answers over the years
and even fooled myself a few times in the first few years. Very few
people know much about topology, but we have seen a fair bit of it here,
especially in the last couple of years. If any of our younger members
have been interested in those message threads, I encourage you to take a
class in topology if you get the chance.

To Andrey's point, I think I can safely say that the flaw cannot be
easily fixed. Pretty much all the great mathematicians over the last 350
years have tried and failed. That is not to say that it can't be done;
it just can't be done easily. The first real proof of the 4-color
conjecture relied very heavily on computer assistance and the result was
so long that it could never be checked by humans. Even if someone
succeeded in following the entire proof, the likelihood that they made a
mistake somewhere is so high that their result couldn't be trusted. The
best they could do is examine the source code for holes or bugs. To make
matters worse, the form of the proof is called a statistical proof
. I had never heard the
term before but it is like "deductive" and "inductive", or like our
false proof "by contradiction". My understanding is that a proper
statistical proof asserts that the odds that there is a counterexample
is vanishingly small. Such proofs are so unpleasant that nobody really
wants to use or accept them. They are the weakest form of proof but they
are definitely considered to be valid.

That proof by Appel and Haken was a landmark in mathematics which split
the mathematics community regarding the use of computers compared to the
traditional pencil and paper methods. These days everyone agrees that
computers play an essential role in pure mathematics, but many people
including myself feel a bit sad that such a beautiful problem didn't
have an equally beautiful solution. There is still a great deal of fame
awaiting the first person who can find an elegant solution that can be
verified the old-fashioned way. The problem is that the goal of being
the first to solve it has already been reached, reducing the fame you
might get if you succeed. Personally, I believe that there will be
plenty of fame for doing that because the purists will be so happy to
see this beautiful problem wrapped up properly.

For a little background showing even more irony, it is helpful to know
that the problem is the same in the plane as it is on the sphere which
are equivalent. These surfaces have genus 0. The one holed torus has
genus 1, two holed 2, etc. for all of the orientable surfaces. Then
there are the non-orientable surfaces like the Klein bottle with genus 1
which are sort of like the negative integers assigned to the one holed
Klein bottle, the two holed bottle, etc. In modern history, little by
little people found solutions to the coloring problem for all of of this
infinite set of surfaces except for genus zero! A lot of really
important results came from that effort, but the one last surface simply
wouldn't yield to those methods, and of course this was the one surface
that everyone cared about the most. I think that Appel and Haken deserve
far more credit than they got, but I still hope and even expect that
someday some hero will finish the job in a way that will satisfy
everyone. I will even offer a $5,000 prize right here and now to anyone
in our group who succeeds in fixing this false proof before anyone else
finds a proof that doesn't require computers. If any of you do take the
prize, the money will probably be the least interesting that happens to
you as a result. Good luck!

-Melinda

On 11/11/2012 11:35 AM, Norbert Hantos wrote:
> Dear Melinda,
>
> I surprised that such a few solutions you get for the false proof of
> the 4-color theorem. Therefore I tried to find the flaw. I think I
> successed. :)
>
> I draw a counter-example graph, where you can not execute the
> recoloring described in 14) and 15).


On 11/11/2012 3:07 AM, Andrey wrote:
> Hi Melinda,
> I haven't read bottom of your message, but in the proof I don't like items 14-15: what if blue-green chain will intersect with red-green? In that case you can't isolate both yellow areas, but I'm not sure if this case can be fixed easily.



--------------000301090302010805070305
Content-Type: text/html; charset=ISO-8859-1
Content-Transfer-Encoding: 7bit



http-equiv="Content-Type">


Both Andrey and Norbert
are correct and have now doubled the number of solvers. Norber's
was sent to me privately and included a nice counterexample. He
was surprised with the dearth of solvers, but I think that our
group is much better equipped for this sort of puzzle than the
general puzzling community. Maybe one of you who also participate
in the speedsolving forums would like to post the puzzle there and
we will see if my guess is right? I have gotten lots of wrong
answers over the years and even fooled myself a few times in the
first few years. Very few people know much about topology, but we
have seen a fair bit of it here, especially in the last couple of
years. If any of our younger members have been interested in those
message threads, I encourage you to take a class in topology if
you get the chance.



To Andrey's point, I think I can safely say that the flaw cannot
be easily fixed. Pretty much all the great mathematicians over the
last 350 years have tried and failed. That is not to say that it
can't be done; it just can't be done easily. The first real proof
of the 4-color conjecture relied very heavily on computer
assistance and the result was so long that it could never be
checked by humans. Even if someone succeeded in following the
entire proof, the likelihood that they made a mistake somewhere is
so high that their result couldn't be trusted. The best they could
do is examine the source code for holes or bugs. To make matters
worse, the form of the proof is called a href="http://en.wikipedia.org/wiki/Statistical_proof">statistical

proof. I had never heard the term before but it is like
"deductive" and "inductive", or like our false proof "by
contradiction". My understanding is that a proper statistical
proof asserts that the odds that there is a counterexample is
vanishingly small. Such proofs are so unpleasant that nobody
really wants to use or accept them. They are the weakest form of
proof but they are definitely considered to be valid.



That proof by Appel and Haken was a landmark in mathematics which
split the mathematics community regarding the use of computers
compared to the traditional pencil and paper methods. These days
everyone agrees that computers play an essential role in pure
mathematics, but many people including myself feel a bit sad that
such a beautiful problem didn't have an equally beautiful
solution. There is still a great deal of fame awaiting the first
person who can find an elegant solution that can be verified the
old-fashioned way. The problem is that the goal of being the first
to solve it has already been reached, reducing the fame you might
get if you succeed. Personally, I believe that there will be
plenty of fame for doing that because the purists will be so happy
to see this beautiful problem wrapped up properly.



For a little background showing even more irony, it is helpful to
know that the problem is the same in the plane as it is on the
sphere which are equivalent. These surfaces have genus 0. The one
holed torus has genus 1, two holed 2, etc. for all of the
orientable surfaces. Then there are the non-orientable surfaces
like the Klein bottle with genus 1 which are sort of like the
negative integers assigned to the one holed Klein bottle, the two
holed bottle, etc. In modern history, little by little people
found solutions to the coloring problem for all of of this
infinite set of surfaces except for genus zero! A lot of really
important results came from that effort, but the one last surface
simply wouldn't yield to those methods, and of course this was the
one surface that everyone cared about the most. I think that Appel
and Haken deserve far more credit than they got, but I still  hope
and even expect that someday some hero will finish the job in a
way that will satisfy everyone. I will even offer a $5,000 prize
right here and now to anyone in our group who succeeds in fixing
this false proof before anyone else finds a proof that doesn't
require computers. If any of you do take the prize, the money will
probably be the least interesting that happens to you as a result.
Good luck!



-Melinda



On 11/11/2012 11:35 AM, Norbert
Hantos wrote:


cite="mid:CABPbRng+hM29GYfr5hqJYwn5TV-=LvLbhQa=uaJj49v+uW9qgA@mail.gmail.com"
type="cite">Dear Melinda,



I surprised that such a few solutions you get for the false
proof of the 4-color theorem. Therefore I tried to find the
flaw. I think I successed. :)




I draw a counter-example graph, where you can not execute
the recoloring described in 14) and 15).






On 11/11/2012 3:07 AM, Andrey wrote:



Hi Melinda,
I haven't read bottom of your message, but in the proof I don't like items 14-15: what if blue-green chain will intersect with red-green? In that case you can't isolate both yellow areas, but I'm not sure if this case can be fixed easily.










--------------000301090302010805070305--




From: "Eduard Baumann" <baumann@mcnet.ch>
Date: Mon, 12 Nov 2012 09:28:56 +0100
Subject: Re: [MC4D] Re: flaw in 4 color theorem "proof"



------=_NextPart_000_0008_01CDC0B8.23A3DF70
Content-Type: text/plain;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable

Thanks.
A perfect recapitulation!
Ed

----- Original Message -----=20
From: Melinda Green=20
To: 4D_Cubing@yahoogroups.com=20
Sent: Monday, November 12, 2012 3:36 AM
Subject: Re: [MC4D] Re: flaw in 4 color theorem "proof"


=20=20=20=20

Both Andrey and Norbert are correct and have now doubled the number of so=
lvers. Norber's was sent to me privately and included a nice counterexample=
. He was surprised with the dearth of solvers, but I think that our group i=
s much better equipped for this sort of puzzle than the general puzzling co=
mmunity. Maybe one of you who also participate in the speedsolving forums w=
ould like to post the puzzle there and we will see if my guess is right? I =
have gotten lots of wrong answers over the years and even fooled myself a f=
ew times in the first few years. Very few people know much about topology, =
but we have seen a fair bit of it here, especially in the last couple of ye=
ars. If any of our younger members have been interested in those message th=
reads, I encourage you to take a class in topology if you get the chance.

To Andrey's point, I think I can safely say that the flaw cannot be easil=
y fixed. Pretty much all the great mathematicians over the last 350 years h=
ave tried and failed. That is not to say that it can't be done; it just can=
't be done easily. The first real proof of the 4-color conjecture relied ve=
ry heavily on computer assistance and the result was so long that it could =
never be checked by humans. Even if someone succeeded in following the enti=
re proof, the likelihood that they made a mistake somewhere is so high that=
their result couldn't be trusted. The best they could do is examine the so=
urce code for holes or bugs. To make matters worse, the form of the proof i=
s called a statistical proof. I had never heard the term before but it is l=
ike "deductive" and "inductive", or like our false proof "by contradiction"=
. My understanding is that a proper statistical proof asserts that the odds=
that there is a counterexample is vanishingly small. Such proofs are so un=
pleasant that nobody really wants to use or accept them. They are the weake=
st form of proof but they are definitely considered to be valid.

That proof by Appel and Haken was a landmark in mathematics which split t=
he mathematics community regarding the use of computers compared to the tra=
ditional pencil and paper methods. These days everyone agrees that computer=
s play an essential role in pure mathematics, but many people including mys=
elf feel a bit sad that such a beautiful problem didn't have an equally bea=
utiful solution. There is still a great deal of fame awaiting the first per=
son who can find an elegant solution that can be verified the old-fashioned=
way. The problem is that the goal of being the first to solve it has alrea=
dy been reached, reducing the fame you might get if you succeed. Personally=
, I believe that there will be plenty of fame for doing that because the pu=
rists will be so happy to see this beautiful problem wrapped up properly.

For a little background showing even more irony, it is helpful to know th=
at the problem is the same in the plane as it is on the sphere which are eq=
uivalent. These surfaces have genus 0. The one holed torus has genus 1, two=
holed 2, etc. for all of the orientable surfaces. Then there are the non-o=
rientable surfaces like the Klein bottle with genus 1 which are sort of lik=
e the negative integers assigned to the one holed Klein bottle, the two hol=
ed bottle, etc. In modern history, little by little people found solutions =
to the coloring problem for all of of this infinite set of surfaces except =
for genus zero! A lot of really important results came from that effort, bu=
t the one last surface simply wouldn't yield to those methods, and of cours=
e this was the one surface that everyone cared about the most. I think that=
Appel and Haken deserve far more credit than they got, but I still hope a=
nd even expect that someday some hero will finish the job in a way that wil=
l satisfy everyone. I will even offer a $5,000 prize right here and now to =
anyone in our group who succeeds in fixing this false proof before anyone e=
lse finds a proof that doesn't require computers. If any of you do take the=
prize, the money will probably be the least interesting that happens to yo=
u as a result. Good luck!

-Melinda


On 11/11/2012 11:35 AM, Norbert Hantos wrote:

Dear Melinda,=20


I surprised that such a few solutions you get for the false proof of th=
e 4-color theorem. Therefore I tried to find the flaw. I think I successed.=
:)


I draw a counter-example graph, where you can not execute the recolorin=
g described in 14) and 15).



On 11/11/2012 3:07 AM, Andrey wrote:

Hi Melinda,
I haven't read bottom of your message, but in the proof I don't like item=
s 14-15: what if blue-green chain will intersect with red-green? In that ca=
se you can't isolate both yellow areas, but I'm not sure if this case can b=
e fixed easily.



=20=20
------=_NextPart_000_0008_01CDC0B8.23A3DF70
Content-Type: text/html;
charset="iso-8859-1"
Content-Transfer-Encoding: quoted-printable



>


Thanks.

A perfect recapitulation!

Ed

 

style=3D"BORDER-LEFT: #000000 2px solid; PADDING-LEFT: 5px; PADDING-RIGHT: =
0px; MARGIN-LEFT: 5px; MARGIN-RIGHT: 0px">
----- Original Message -----

style=3D"FONT: 10pt arial; BACKGROUND: #e4e4e4; font-color: black">Fro=
m:
=20
href=3D"mailto:melinda@superliminal.com">Melinda Green

To: ps.com=20
href=3D"mailto:4D_Cubing@yahoogroups.com">4D_Cubing@yahoogroups.com
<=
/DIV>
Sent: Monday, November 12, 2012 3:=
36=20
AM

Subject: Re: [MC4D] Re: flaw in 4 =
color=20
theorem "proof"


 =20


Both Andrey and Norbert are c=
orrect=20
and have now doubled the number of solvers. Norber's was sent to me priva=
tely=20
and included a nice counterexample. He was surprised with the dearth of=20
solvers, but I think that our group is much better equipped for this sort=
of=20
puzzle than the general puzzling community. Maybe one of you who also=20
participate in the speedsolving forums would like to post the puzzle ther=
e and=20
we will see if my guess is right? I have gotten lots of wrong answers ove=
r the=20
years and even fooled myself a few times in the first few years. Very few=
=20
people know much about topology, but we have seen a fair bit of it here,=
=20
especially in the last couple of years. If any of our younger members hav=
e=20
been interested in those message threads, I encourage you to take a class=
in=20
topology if you get the chance.

To Andrey's point, I think I can s=
afely=20
say that the flaw cannot be easily fixed. Pretty much all the great=20
mathematicians over the last 350 years have tried and failed. That is not=
to=20
say that it can't be done; it just can't be done easily. The first real p=
roof=20
of the 4-color conjecture relied very heavily on computer assistance and =
the=20
result was so long that it could never be checked by humans. Even if some=
one=20
succeeded in following the entire proof, the likelihood that they made a=
=20
mistake somewhere is so high that their result couldn't be trusted. The b=
est=20
they could do is examine the source code for holes or bugs. To make matte=
rs=20
worse, the form of the proof is called a href=3D"http://en.wikipedia.org/wiki/Statistical_proof">statistical proof=
. I=20
had never heard the term before but it is like "deductive" and "inductive=
", or=20
like our false proof "by contradiction". My understanding is that a prope=
r=20
statistical proof asserts that the odds that there is a counterexample is=
=20
vanishingly small. Such proofs are so unpleasant that nobody really wants=
to=20
use or accept them. They are the weakest form of proof but they are defin=
itely=20
considered to be valid.

That proof by Appel and Haken was a landma=
rk in=20
mathematics which split the mathematics community regarding the use of=20
computers compared to the traditional pencil and paper methods. These day=
s=20
everyone agrees that computers play an essential role in pure mathematics=
, but=20
many people including myself feel a bit sad that such a beautiful problem=
=20
didn't have an equally beautiful solution. There is still a great deal of=
fame=20
awaiting the first person who can find an elegant solution that can be=20
verified the old-fashioned way. The problem is that the goal of being the=
=20
first to solve it has already been reached, reducing the fame you might g=
et if=20
you succeed. Personally, I believe that there will be plenty of fame for =
doing=20
that because the purists will be so happy to see this beautiful problem=20
wrapped up properly.

For a little background showing even more iro=
ny,=20
it is helpful to know that the problem is the same in the plane as it is =
on=20
the sphere which are equivalent. These surfaces have genus 0. The one hol=
ed=20
torus has genus 1, two holed 2, etc. for all of the orientable surfaces. =
Then=20
there are the non-orientable surfaces like the Klein bottle with genus 1 =
which=20
are sort of like the negative integers assigned to the one holed Klein bo=
ttle,=20
the two holed bottle, etc. In modern history, little by little people fou=
nd=20
solutions to the coloring problem for all of of this infinite set of surf=
aces=20
except for genus zero! A lot of really important results came from that=20
effort, but the one last surface simply wouldn't yield to those methods, =
and=20
of course this was the one surface that everyone cared about the most. I =
think=20
that Appel and Haken deserve far more credit than they got, but I still&n=
bsp;=20
hope and even expect that someday some hero will finish the job in a way =
that=20
will satisfy everyone. I will even offer a $5,000 prize right here and no=
w to=20
anyone in our group who succeeds in fixing this false proof before anyone=
else=20
finds a proof that doesn't require computers. If any of you do take the p=
rize,=20
the money will probably be the least interesting that happens to you as a=
=20
result. Good luck!

-Melinda


On 11/11/2012 11:35 AM, Norbert Hantos=20
wrote:

cite=3Dmid:CABPbRng+hM29GYfr5hqJYwn5TV-=3DLvLbhQa=3DuaJj49v+uW9qgA@mail.g=
mail.com=20
type=3D"cite">Dear Melinda,=20


I surprised that such a few solutions you get for the false proof =
of=20
the 4-color theorem. Therefore I tried to find the flaw. I think I=20
successed. :)



I draw a counter-example graph, where you can not execute the=20
recoloring described in 14) and 15).



On 11/11/2012 3:07 AM, Andrey wrote:
V>
"">Hi Melinda,
I haven't read bottom of your message, but in the proof I don't like item=
s 14-15: what if blue-green chain will intersect with red-green? In that ca=
se you can't isolate both yellow areas, but I'm not sure if this case can b=
e fixed easily.





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