Thread: "More {3,3,8} pics and new {3,8} MagicTile puzzles [1 Attachment]"

From: Roice Nelson <roice3@gmail.com>
Date: Sun, 12 Aug 2012 18:16:17 -0500
Subject: Re: [MC4D] More {3,3,8} pics and new {3,8} MagicTile puzzles [1 Attachment]



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Nice!

Sorry for the long delay in responding. I'm not able to describe the
construction as well as you, because the MagicTile code is doing most of
the work for me. The way it works is that you construct a set of
"identifications". You do this by configuring edges to reflect across to
go from the central white tile to an identified copy. It internally
calculates the associated isometries, and uses those to recursively copy
tiles all over the plane. One consequence is that you can take some tile
to one of its copies, and the whole coloring will remain unchanged. So
while your coloring has multiple kinds of red tiles, every red tile in my
coloring is the same - each is surrounded by the purple/cyan/green tiles.
MagicTile could not reproduce the coloring you've found (without setting
multiple tiles to the same color). I think your coloring might be a
16-coloring in disguise.

Anyway, here's how I went. I started by mentally grouping together a set
of 8 triangles into an octagon, then picked an identification which would
make copies of the 8-color pattern along an h-line. This gave me a line of
stacked octagons where every other octagon was mirrored. The h-line goes
through the center of the white/green tiles. Then I picked additional
identifications to fill in the two areas to either side of this h-line, and
those resulted in the stripe of 3 colors. Though I've gotten an intuitive
feel for configuring these, it still involves trial and error for me, and
it's magical when things "click" together, filling in the whole plane. Let
me know if you'd like more info on the MagicTile configuration (they are
xml files, editable by hand). The format is not perfect for sure, but I
did try to make it clear.

Btw, Melinda described the {3,3,8} image to me as consisting "of a full
color background with an overlaid black & white lace doily with windows
through which you can see parts of the background". I liked that mental
image. The "full color background" without the lace looks like a colored
{3,8} tiling in the disk, plus its inversion in the disk boundary, like
this:

www.gravitation3d.com/roice/math/ultrainf/338/38_8C_with_inverse.png

Here is the {3,3,8} image again, for reference:

http://gravitation3d.com/roice/math/ultrainf/338/338_neighbors_8C.png

seeya,
Roice



On Thu, Aug 2, 2012 at 1:00 PM, Don Hatch wrote:

> Hey Roice,
>
> These are looking great. I get a good sense of where the cells are
> now, especially in the half-plane one.
>
> How did you construct your 8-coloring for the {3,8}?
>
> I came up with a periodic coloring, but it's not the same as yours--
> I see that yours has stripes of 3 colors (grey,yellow,blue)
> going through it, but mine doesn't have any such stripes.
>
> I'm attaching an image of mine (not sure whether this will work).
>
> Here's how I construct it...
> Imagine the {3,8} partitioned into an {8,4}
> (8 triangles of the {3,8} in each octagon of the {8,4}).
> Call half of the octagons "even" and the other half "odd",
> in a checkerboard pattern.
> Start with any even octagon, and color its 8 triangles
> counterclockwise: 0 1 2 3 4 5 6 7.
> Then for each of the eight even octagons
> "diagonal" to the first even octagon,
> again color it CCW with 0 1 2 3 4 5 6 7,
> in the same orientation as the first even octagon
> (so, for example, one of them will have its 4 5
> sharing a vertex with the first octagon's 0 1).
> Continue in this way, coloring all even octagons.
>
> Finally, for each not-yet-colored triangle (in an odd octagon),
> color it ((i+2) mod 8) where i is the color of its
> already-colored neighbor triangle (in an even octagon).
> This gives each odd octagon the colors 0 3 6 1 4 7 2 5, counterclockwise.
>
> ((i+6) mod 8) could be used instead of ((i+2) mod 8).
>
> Don
>
>

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Nice!


Sorry for the long delay in responding. =A0I'm=
not able to describe the construction as well as you, because the MagicTil=
e code is doing most of the work for me. =A0The way it works is that you co=
nstruct a set of "identifications". =A0You do this by configuring=
edges to reflect across to go from the central white tile to an identified=
copy. =A0It internally calculates the associated isometries, and uses thos=
e to recursively copy tiles all over the plane. =A0One consequence is that =
you can take some tile to one of its copies, and the whole coloring will re=
main unchanged. =A0So while your coloring has multiple kinds of red tiles, =
every red tile in my coloring is the same - each is surrounded by the purpl=
e/cyan/green tiles. =A0MagicTile could not reproduce the coloring you'v=
e found (without setting multiple tiles to the same color). =A0I think your=
coloring might be a 16-coloring in disguise.



Anyway, here's how I went. =A0I started=A0by mental=
ly grouping together a set of 8 triangles into an octagon, then picked an i=
dentification which would make copies of the 8-color pattern along an h-lin=
e. =A0This gave me a line of stacked octagons where every other octagon was=
mirrored. =A0The h-line goes through the center of the white/green tiles. =
=A0Then I picked additional identifications to fill in the two areas to eit=
her side of this h-line, and those resulted in the stripe of 3 colors. =A0T=
hough I've gotten an intuitive feel for configuring these, it still inv=
olves trial and error for me, and it's magical when things "click&=
quot; together, filling in the whole plane. =A0Let me know if you'd lik=
e more info on the MagicTile configuration (they are xml files, editable by=
hand). =A0The format is not perfect for sure, but I did try to make it cle=
ar.





Btw, Melinda described the {3,3,8} image to me as consi=
sting "of a full color background with an overlaid black & white l=
ace doily with windows through which you can see parts of the background&qu=
ot;. =A0I liked that mental image. =A0The "full color background"=
without the lace looks like a colored {3,8} tiling in the disk, plus its i=
nversion in the disk boundary, like this:



ith_inverse.png" target=3D"_blank">www.gravitation3d.com/roice/math/ultrain=
f/338/38_8C_with_inverse.png


Here is the {3,3,8} image again, fo=
r reference:



/338/338_neighbors_8C.png" target=3D"_blank">http://gravitation3d.com/roice=
/math/ultrainf/338/338_neighbors_8C.png
=A0

seeya,
Roic=
e





On Thu, Aug 2, 2012 at 1=
:00 PM, Don Hatch <target=3D"_blank">hatch@plunk.org> wrote:


x #ccc solid;padding-left:1ex"><*>[Attachment(s) from Don Hatch inclu=
ded below]



Hey Roice,



These are looking great. =A0I get a good sense of where the cells are

now, especially in the half-plane one.



How did you construct your 8-coloring for the {3,8}?



I came up with a periodic coloring, but it's not the same as yours-->
I see that yours has stripes of 3 colors (grey,yellow,blue)

going through it, but mine doesn't have any such stripes.



I'm attaching an image of mine (not sure whether this will work).



Here's how I construct it...

Imagine the {3,8} partitioned into an {8,4}

(8 triangles of the {3,8} in each octagon of the {8,4}).

Call half of the octagons "even" and the other half "odd&quo=
t;,

in a checkerboard pattern.

Start with any even octagon, and color its 8 triangles

counterclockwise: 0 1 2 3 4 5 6 7.

Then for each of the eight even octagons

"diagonal" to the first even octagon,

again color it CCW with 0 1 2 3 4 5 6 7,

in the same orientation as the first even octagon

(so, for example, one of them will have its 4 5

sharing a vertex with the first octagon's 0 1).

Continue in this way, coloring all even octagons.



Finally, for each not-yet-colored triangle (in an odd octagon),

color it ((i+2) mod 8) where i is the color of its

already-colored neighbor triangle (in an even octagon).

This gives each odd octagon the colors 0 3 6 1 4 7 2 5, counterclockwise.r>


((i+6) mod 8) could be used instead of ((i+2) mod 8).



Don



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