oNormal>color:#1F497D'>I have emails I've been wanting to catch up on starting back= rmal>or:#1F497D'>(I'm only considering face twists in this email--i.e. (N-1)D fa= <= size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'>QFTM =3D &quo= ily:"Calibri","sans-serif";color:#1F497D'>QSTM =3D "90 degree twists o= =3D'font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'>AAFT= yle=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'><= .0pt;font-family:"Calibri","sans-serif";color:#1F497D'>Surprisingly enough,= MsoNormal>";color:#1F497D'> le=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'>ta= lass=3DMsoNormal>s-serif";color:#1F497D'>2^4 = ly:"Calibri","sans-serif";color:#1F497D'>3^4 &= :11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'> :"Calibri","sans-serif";color:#1F497D'>Although this counting method yields= ize:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'> ily:"Calibri","sans-serif";color:#1F497D'>-- =3DMsoNormal>rif";color:#1F497D'>Andy yle=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F497D'><= .0pt;font-family:"Calibri","sans-serif";color:#1F497D'> pt;font-family:"Tahoma","sans-serif"'>From:ize:10.0pt;font-family:"Tahoma","sans-serif"'> 4D_Cubing@yahoogroups.com [m= oNormal> I'd like to see results here as we= Since I can't seem to help myself from making&nbs= =3DMsoNormal> I don't r= Take Care, MsoNormal>Roice On Fri, Jul 1, 2011 at 4:41 AM,= ass=3DMsoNormal style=3D'margin-bottom:12.0pt'> How= idea for the likely l= be some some heuristic results availa= but in particular the quarter-turn one. Sorr= :white'>
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I have emails I've been wanting to catch up on starting back with
goldilocks.. Anyhoo, as it turns out, I had already been working on finding
lower bounds using counting arguments WHEN the twist metric is extremely
well defined.
(I'm only considering face twists in this email--i.e. (N-1)D face twists.)
For example,
QFTM = "90 degree twists of faces are allowed and that's it";
QSTM = "90 degree twists of slices" (MC5D)
AAFTM (atomic angle face.) = if it's possible to do a 90-degree face twist,
the equivalent 180 counts as 2 twists;
AASTM (atomic angle slice.) = MC4D's counting method.
Surprisingly enough, QFTM on the 3^4 is the one that took the most work.
Here's the lower bounds for God's number that I calculate:
table: QFTM FTM
2^4 22 16
3^4 75 56
Although this counting method yields a lower bound of 18 for the 3^3 FTM
(where we now know it's 20), the same method for the 2^3 QTM yields a lower
bound of 10 where God's number is known to be 14. So it's difficult to say
how decent these bounds are--especially when we don't know (and can't
compare) God's number for any 4D (or higher) cube with twist metrics that
yield the full number of attainable states via face twists. Nonetheless,
lower bounds have historically been closer to the actual God's number than
the upper bounds, so if you wanted to take a guess at the actual number I'd
say, go slightly greater than these.
--
Andy
From: 4D_Cubing@yahoogroups.com [mailto:4D_Cubing@yahoogroups.com] On Behalf
Of Roice Nelson
Sent: Friday, July 01, 2011 19:54
To: 4D_Cubing@yahoogroups.com
Subject: Re: [MC4D] Re: God's Number for n^3 cubes.
I'd like to see results here as well, though it is a very different kind of
problem than the one Nan proposed.
Since I can't seem to help myself from making predictions, mine here is that
things will follow what happened for the 3^3. That is, the lower/upper
bounds will get squeezed together over an extended time (the upper bound
requiring more effort) using group theory arguments, but that the group
theory arguments will run out of steam. cube20.org has a tabular history of
the 20 year saga to find God's Number for Rubik's Cube. Since they had to
finish off the final gap with computers, which will be impossible for the
3^4, the exact answer may literally never be known. Maybe the 2^4 will be
tractable though.
I don't recall specific bounds being mathematically defended here before,
but I may very well have missed them or may be forgetting. Perhaps some
wiki pages for God's Algorithm are in order to begin collating what we know.
We could have separate pages for the asymptotic and low-dimensional
problems.
Take Care,
Roice
On Fri, Jul 1, 2011 at 4:41 AM, PAUL TIMMONS
wrote:
How about restricting oneself to God's algorithm for the 3^4 case? I wanted
to get an
idea for the likely length of God's algorithm (both in the QTM and the FTM).
There must
be some some heuristic results available now that the MC4D has been in use
for some years now. Even more so I am interested in any results for the 2^4
case in both metrics
but in particular the quarter-turn one. Sorry if this information is in
circulation elsewhere - too much information to sift through and too little
time!
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xmlns:m=3D"http://schemas.microsoft.com/office/2004/12/omml" xmlns=3D"http:=
//www.w3.org/TR/REC-html40">=3D"text/html; charset=3Dus-ascii">oft Word 12 (filtered medium)"> link=3D"#1E66AE" vlink=3D"#1E66AE">
with goldilocks…. Anyhoo, as it turns out, I had already been =
working on finding lower bounds using counting arguments WHEN the twist met=
ric is extremely well defined.
ce twists.) For example,
span style=3D'font-size:11.0pt;font-family:"Calibri","sans-serif";color:#1F=
497D'>
t;90 degree twists of faces are allowed and that's it";
f slices" (MC5D)
M (atomic angle face…) =3D if it's possible to do a 90-degree face tw=
ist, the equivalent 180 counts as 2 twists;
counting method.
o:p>
QFTM on the 3^4 is the one that took the most work. Here's the lower=
bounds for God's number that I calculate:
ble: QFTM FTM
22 16
nbsp; 75 &=
nbsp; 56
a lower bound of 18 for the 3^3 FTM (where we now know it's 20), the same =
method for the 2^3 QTM yields a lower bound of 10 where God's number is kno=
wn to be 14. So it's difficult to say how decent these bounds are--es=
pecially when we don't know (and can't compare) God's number for any 4D (or=
higher) cube with twist metrics that yield the full number of attainable s=
tates via face twists. Nonetheless, lower bounds have historically be=
en closer to the actual God's number than the upper bounds, so if you wante=
d to take a guess at the actual number I'd say, go slightly greater than th=
ese.
o:p>
ailto:4D_Cubing@yahoogroups.com] On Behalf Of Roice Nelson
Sen=
t: Friday, July 01, 2011 19:54
To: 4D_Cubing@yahoogroups.com<=
br>Subject: Re: [MC4D] Re: God's Number for n^3 cubes.
ll, though it is a very different kind of problem than the one Nan proposed=
.
p;predictions, mine here is that things will follow what happened for the 3=
^3. That is, the lower/upper bounds will get squeezed together over a=
n extended time (the upper bound requiring more effort) using group theory =
arguments, but that the group theory arguments will run out of steam. =
cube20.org has a tabul=
ar history of the 20 year saga to find God's Number for Rubik's Cube. =
Since they had to finish off the final gap with computers, which will be i=
mpossible for the 3^4, the exact answer may literally never be known.  =
;Maybe the 2^4 will be tractable though.
ecall specific bounds being mathematically defended here before, but I may =
very well have missed them or may be forgetting. Perhaps some wiki pa=
ges for God's Algorithm are in order to begin collating what we know.  =
;We could have separate pages for the asymptotic and low-dimensional proble=
ms.
PAUL TIMMONS <_blank">paul.timmons@btinternet.com> wrote:class=3DMsoNormalTable border=3D0 cellspacing=3D0 cellpadding=3D0>
align=3Dtop style=3D'padding:0in 0in 0in 0in'>
about restricting oneself to God's algorithm for the 3^4 case? I wanted to=
get an
ength of God's algorithm (both in the QTM and the FTM). There must
ble now that the MC4D has been in use for some years now. Even more so I am=
interested in any results for the 2^4 case in both metrics
/div>
y if this information is in circulation elsewhere - too much information to=
sift through and too little time!
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11pt">I have emails I've been wanting to catch up on starting back with gol= 11pt">(I'm only considering face twists in this email--i.e. (N-1)D face twi= 11pt"> 11pt">QFTM =3D "90 degree twists of faces are allowed and that's it";  = 11pt">QSTM =3D "90 degree twists of slices" (MC5D) 11pt">AAFTM (atomic angle face=E2=80=A6) =3D if it's possible to do a 90-de= 11pt">AASTM (atomic angle slice=E2=80=A6) =3D MC4D's counting method.= 11pt"> 11pt">Surprisingly enough, QFTM on the 3^4 is the one that took the most wo= 11pt"> 11pt">table: QFTM FTM 11pt">2^4 22 &nb= 11pt">3^4 75 &nb= 11pt"> 11pt">Although this counting method yields a lower bound of 18 for the 3^3 = 11pt"> 11pt">-- 11pt">Andy 11pt"> 11pt"> From:= I'd like to see results here as well, thou= Since I can't seem to help myself from mak= I don't recall specific bounds being mathe= Take Care, Roice On Fri, Jul 1, 2011 at 4:41 AM, PAUL TIMMO= How about restricting oneself to God's alg= idea for the likely length of God's algori= be some some heuristic results available n= but in particular the quarter-turn one. So= =
=C2=A0=20
I have emails I've been wanting to catch up on starting back with goldilock=
s=E2=80=A6.=C2=A0 Anyhoo, as it turns out, I had already been working on fi=
nding lower bounds using counting arguments WHEN the twist metric is extrem=
ely well defined.=C2=A0=20
(I'm only considering face twists in this email--i.e. (N-1)D face twists.)=
=C2=A0 For example,=20
=C2=A0
QFTM =3D "90 degree twists of faces are allowed and that's it"; =C2=A0
QSTM =3D "90 degree twists of slices" (MC5D)
AAFTM (atomic angle face=E2=80=A6) =3D if it's possible to do a 90-degree f=
ace twist, the equivalent 180 counts as 2 twists;=C2=A0=20
AASTM (atomic angle slice=E2=80=A6) =C2=A0=3D MC4D's counting method. =C2=
=A0
=C2=A0
Surprisingly enough, QFTM on the 3^4 is the one that took the most work.=C2=
=A0 Here's the lower bounds for God's number that I calculate:
=C2=A0
table:=C2=A0=C2=A0=C2=A0 QFTM=C2=A0=C2=A0=C2=A0 FTM
2^4=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 22=C2=A0=C2=A0=C2=A0=C2=
=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 16
3^4=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 75=C2=A0=C2=A0=C2=A0=C2=
=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0=C2=A0 56
=C2=A0
Although this counting method yields a lower bound of 18 for the 3^3 FTM (w=
here we now know it's 20), the same method for the 2^3 QTM yields a lower b=
ound of 10 where God's number is known to be 14. =C2=A0So it's difficult to=
say how decent these bounds are--especially when we don't know (and can't =
compare) God's number for any 4D (or higher) cube with twist metrics that y=
ield the full number of attainable states via face twists.=C2=A0 Nonetheles=
s, lower bounds have historically been closer to the actual God's number th=
an the upper bounds, so if you wanted to take a guess at the actual number =
I'd say, go slightly greater than these.=C2=A0=20
=C2=A0
--
Andy
=C2=A0
=C2=A0
From: 4D_Cubing@yahoogroups.com [mailto:4D_Cubing@yahoogroups.com] On Behal=
f Of Roice Nelson
Sent: Friday, July 01, 2011 19:54
To: 4D_Cubing@yahoogroups.com
Subject: Re: [MC4D] Re: God's Number for n^3 cubes.
=C2=A0
=C2=A0=20
I'd like to see results here as well, though it is a very different kind of=
problem than the one Nan proposed.
=C2=A0
Since I can't seem to help myself from making=C2=A0predictions, mine here i=
s that things will follow what happened for the 3^3. =C2=A0That is, the low=
er/upper bounds will get squeezed together over an extended time (the upper=
bound requiring more effort) using group theory arguments, but that the gr=
oup theory arguments will run out of steam.=C2=A0 cube20.org has a tabular =
history of the 20 year saga to find God's Number for Rubik's Cube.=C2=A0 Si=
nce they had to finish off the final gap with computers, which will be impo=
ssible for the 3^4, the exact answer may literally never be known. =C2=A0Ma=
ybe the 2^4 will be tractable though.
=C2=A0
I don't recall specific bounds being mathematically defended here before, b=
ut I may very well have missed them or may be forgetting. =C2=A0Perhaps som=
e wiki pages for God's Algorithm are in order to begin collating what we kn=
ow. =C2=A0We could have separate pages for the asymptotic and low-dimension=
al problems.
=C2=A0
Take Care,
Roice
=C2=A0
On Fri, Jul 1, 2011 at 4:41 AM, PAUL TIMMONS
wrote:
=C2=A0
How about restricting oneself to God's algorithm for the 3^4 case? I wanted=
to get an
idea for the likely length of God's algorithm (both in the QTM and the FTM)=
. There must
be some some heuristic results available now that the MC4D has been in use =
for some years now. Even more so I am interested in any results for the 2^4=
case in both metrics
but in particular the quarter-turn one. Sorry if this information is in cir=
culation elsewhere - too much information to sift through and too little ti=
me!
=C2=A0
--0-2094008194-1309772239=:17943
Content-Type: text/html; charset=utf-8
Content-Transfer-Encoding: quoted-printabletop" style=3D"font: inherit;">
on that in big O notation that it may take roughly
r 3 and r is the exponent or number of dimensions. Can anyone corroborate t=
his?
re these definitve - you will excuse me if I do not take these results at f=
ace (no pun intended) value. This will I am sure be of interest&=
nbsp;to many people on this forum. As Roice has remarked it would be useful=
to start Wiki'ing up what is known for small r and r->00.
be blank. What message were they supposed to convey?
 =
;On Sun, 3/7/11, Andrew Gould <agould@uwm.edu> wrote:R>
px; MARGIN-LEFT: 5px">
From: Andrew Gould <agould@uwm.edu>
Subj=
ect: [MC4D] RE: God's Number for n^4 cubes.
To: 4D_Cubing@yahoogroups.co=
m
Date: Sunday, 3 July, 2011, 15:33
dilocks=E2=80=A6. Anyhoo, as it turns out, I had already been working=
on finding lower bounds using counting arguments WHEN the twist metric is =
extremely well defined.
sts.) For example,
;
gree face twist, the equivalent 180 counts as 2 twists;
rk. Here's the lower bounds for God's number that I calculate:=
sp; 16
sp; 56
FTM (where we now know it's 20), the same method for the 2^3 QTM yields a l=
ower bound of 10 where God's number is known to be 14. So it's diffic=
ult to say how decent these bounds are--especially when we don't know (and =
can't compare) God's number for any 4D (or higher) cube with twist metrics =
that yield the full number of attainable states via face twists. None=
theless, lower bounds have historically been closer to the actual God's num=
ber than the upper bounds, so if you wanted to take a guess at the actual n=
umber I'd say, go slightly greater than these.
SPAN> 4D_Cubing@yahoogroups.com [mailto=
:4D_Cubing@yahoogroups.com] On Behalf Of Roice Nelson
Sent:> Friday, July 01, 2011 19:54
To: 4D_Cubing@yahoogroups.com
>Subject: Re: [MC4D] Re: God's Number for n^3 cubes.
gh it is a very different kind of problem than the one Nan proposed.
/DIV>
ing predictions, mine here is that things will follow what happened fo=
r the 3^3. That is, the lower/upper bounds will get squeezed together=
over an extended time (the upper bound requiring more effort) using group =
theory arguments, but that the group theory arguments will run out of steam=
. cube2=
0.org has a tabular history of the 20 year saga to find God's Number fo=
r Rubik's Cube. Since they had to finish off the final gap with compu=
ters, which will be impossible for the 3^4, the exact answer may literally =
never be known. Maybe the 2^4 will be tractable though.
matically defended here before, but I may very well have missed them or may=
be forgetting. Perhaps some wiki pages for God's Algorithm are in or=
der to begin collating what we know. We could have separate pages for=
the asymptotic and low-dimensional problems.
NS <ns@btinternet.com" rel=3Dnofollow target=3D_blank ymailto=3D"mailto:paul.ti=
mmons@btinternet.com">paul.timmons@btinternet.com> wrote:dding=3D0>
orithm for the 3^4 case? I wanted to get an
thm (both in the QTM and the FTM). There must
ow that the MC4D has been in use for some years now. Even more so I am inte=
rested in any results for the 2^4 case in both metrics
rry if this information is in circulation elsewhere - too much information =
to sift through and too little time!
--0-2094008194-1309772239=:17943--
=20
On Fri, Jul 1, 2011 at 4:41 AM, PAUL TIMMONS
wrote:
=20
How about restricting oneself to God's algorithm for the 3^4 case? I wanted=
to get an
idea for the likely length of God's algorithm (both in the QTM and the FTM)=
. There must
be some some heuristic results available now that the MC4D has been in use =
for some years now. Even more so I am interested in any results for the 2^4=
case in both metrics
but in particular the quarter-turn one. Sorry if this information is in cir=
culation elsewhere - too much information to sift through and too little ti=
me!
=20
On Fri, Jul 1, 2011 at 4:41 AM, PAUL TIMMONS
wrote:
=20
How about restricting oneself to God's algorithm for the 3^4 case? I wanted=
to get an
idea for the likely length of God's algorithm (both in the QTM and the FTM)=
. There must
be some some heuristic results available now that the MC4D has been in use =
for some years now. Even more so I am interested in any results for the 2^4=
case in both metrics
but in particular the quarter-turn one. Sorry if this information is in cir=
culation elsewhere - too much information to sift through and too little ti=
me!