Thread: "MagicTile Hexa 9 colors length 5 solved"

I used 3101 twists. I will comment later.

My result is 1464 twists. Log is here: http://games.groups.yahoo.com/group/=
4D_Cubing/files/MC7D/andrey_9col_5.log
There was unusual parity problem on the "edge recombination" stage. I don=
't remember it from earlier solves, but it looks like it can appear on any =
"{2n,3}, 5 layers" puzzle.=20

Andrey

--- In 4D_Cubing@yahoogroups.com, "Eduard" wrote:
>
> I used 3101 twists. I will comment later.
>

Hi Andrey,

Can you describe the parity issue? If it can appear in all {2n,3} 5 layers,=
then it should be in 5x5x5, which means it's not that unusual. Thanks.

Nan

--- In 4D_Cubing@yahoogroups.com, "Andrey" wrote:
>
> My result is 1464 twists. Log is here: http://games.groups.yahoo.com/grou=
p/4D_Cubing/files/MC7D/andrey_9col_5.log
> There was unusual parity problem on the "edge recombination" stage. I d=
on't remember it from earlier solves, but it looks like it can appear on an=
y "{2n,3}, 5 layers" puzzle.=20
>=20
> Andrey
>=20
> --- In 4D_Cubing@yahoogroups.com, "Eduard" wrote:
> >
> > I used 3101 twists. I will comment later.
> >
>

Here are my comments

My strategy for the "MagicTile Hexagonal 9 colors length 5" was the followi=
ng

(1)
For
.C.D
A.B.=20=20
collect the edges first with normal twists then with the 3-cycle sequence=20
S1 =3D [[A,B2'],[D2',C]] , B and D second layer, A and C first layer

(2)=20=20
Do the face-edges with the 3-cycle sequence S2 =3D [A,B]^5 where A is layer=
1 and B layer 2

(3)=20=20
Do the edges as I have indicated in KleinsQuartic Document

(4)=20=20
Do the corners as I have indicated in KleinsQuartic Document

(5)
For
.A.B
C.D.
do the face-corners with the 3-cycle sequence=20
S3 =3D [ C'DA2 [A,B'] A2'D'C , [A,B'] ]=20
all second layer turns except D

I feared parity issues but I was lucky.


--- In 4D_Cubing@yahoogroups.com, "Eduard" wrote:
>
> I used 3101 twists. I will comment later.
>

Nan, you are right. It's really usual situation for 5^3 if you solve it b=
y reduction to 3^3. When one combines edges using commutators it may happen=
that he has to swap two cubies (1,1,2) (second cubies of the edge, don't k=
now how you call them) and for that he makes single twist of some 2nd layer=
to restore parity (and continue with commutators).
I haven't remembered this fact because I use different algorithms for the=
reduction: for 5^3 I combine edges before centers, and for {n,3} start wit=
h centers, then combine edges.

Andrey



--- In 4D_Cubing@yahoogroups.com, "schuma" wrote:
>
> Hi Andrey,
>=20
> Can you describe the parity issue? If it can appear in all {2n,3} 5 layer=
s, then it should be in 5x5x5, which means it's not that unusual. Thanks.
>=20
> Nan
>=20
> --- In 4D_Cubing@yahoogroups.com, "Andrey" wrote:
> >
> > My result is 1464 twists. Log is here: http://games.groups.yahoo.com/gr=
oup/4D_Cubing/files/MC7D/andrey_9col_5.log
> > There was unusual parity problem on the "edge recombination" stage. I=
don't remember it from earlier solves, but it looks like it can appear on =
any "{2n,3}, 5 layers" puzzle.=20
> >=20
> > Andrey
> >=20
> > --- In 4D_Cubing@yahoogroups.com, "Eduard" wrote:
> > >
> > > I used 3101 twists. I will comment later.
> > >
> >
>