Thread: "4^4 parity alg"

From: "Jonathan" <jonathan.mecias001@mymdc.net>
Date: Thu, 08 Oct 2009 10:58:39 -0000
Subject: 4^4 parity alg



if anyone is curious on a algorithm that switches 2 pairs of 3-colored piec=
es without messing up anything (even corners!),let me know and ill respond =
with the solution.this algorithm can be useful on other sized cubes. its a =
manipulation of roice's old algorithms; ill use roice's notation to explain=
it. this is the only parity i encountered in my solve(excluding the pariti=
es that can be solved with regular 4*4*4 algorithms). if anyone can show me=
the "Single 3-colour cubie flipped" in a picture or something that would b=
e awsome or maby a description? lol=20=20

cheers from Florida!




From: Klaus Weidinger <klaus.weidinger@yahoo.com>
Date: Thu, 8 Oct 2009 11:30:46 -0700 (PDT)
Subject: Re: [MC4D] 4^4 parity alg







=A0




=20=20=20=20
if anyone is curious on a algorithm that switches 2 pairs=
of 3-colored pieces without messing up anything (even corners!),let me kno=
w and ill respond with the solution..this algorithm can be useful on other =
sized cubes. its a manipulation of roice's old algorithms; ill use roice's =
notation to explain it. this is the only parity i encountered in my solve(e=
xcluding the parities that can be solved with regular 4*4*4 algorithms). if=
anyone can show me the "Single 3-colour cubie flipped" in a picture or som=
ething that would be awsome or maby a description? lol=20=20



cheers from Florida!




=20

=20=20=20=20=20=20

=20=20=20=20
=20=20=20=20
=09
=09=20
=09
=09








=09


=09
=09


=20=20=20=20=20=20
--0-200014811-1255026646=:6222
Content-Type: text/html; charset=iso-8859-1
Content-Transfer-Encoding: quoted-printable

top" style=3D"font: inherit;">Hi Jonathan,

If you would find a simil=
ar algorithm for the 3^4 I would really appreciate to hear of it, because I=
'm doing corners first and therefore the 3c-pieces are the last ones to sol=
ve
for me.

Have a nice twist,
Klaus

--- On Thu, 10/8=
/09, Jonathan <jonathan.mecias001@mymdc.net>
wrote:
ockquote style=3D"border-left: 2px solid rgb(16, 16, 255); margin-left: 5px=
; padding-left: 5px;">
From: Jonathan <jonathan.mecias001@mymdc.net&g=
t;
Subject: [MC4D] 4^4 parity alg
To: 4D_Cubing@yahoogroups.com
Da=
te: Thursday, October 8, 2009, 10:58 AM






 


if anyone is curious on a algorithm that switches 2 pa=
irs of 3-colored pieces without messing up anything (even corners!),let me =
know and ill respond with the solution.this algorithm can be useful on othe=
r sized cubes. its a manipulation of roice's old algorithms; ill use roice'=
s notation to explain it. this is the only parity i encountered in my solve=
(excluding the parities that can be solved with regular 4*4*4 algorithms). =
if anyone can show me the "Single 3-colour cubie flipped" in a picture or s=
omething that would be awsome or maby a description? lol



cheers from Florida!




=20

=20=20


=09=20
=09



=20=20=20=20=20=20
--0-200014811-1255026646=:6222--




From: "Jonathan" <jonathan.mecias001@mymdc.net>
Date: Thu, 08 Oct 2009 20:22:33 -0000
Subject: Re: [MC4D] 4^4 parity alg



yes actually i do. though i dont use ur method of solving the cube i was ab=
le to come up with a simple algorithm that can manage and satisfy your tast=
e. i also feel that if you are not experienced with parities, your method i=
s suppirior to mine. i'm late for school so ill have to post in a few hours=
.=20

laters
=20
--- In 4D_Cubing@yahoogroups.com, Klaus Weidinger wro=
te:
>
> Hi Jonathan,
>=20
> If you would find a similar algorithm for the 3^4 I would really apprecia=
te to hear of it, because I'm doing corners first and therefore the 3c-piec=
es are the last ones to solve
> for me.
>=20
> Have a nice twist,
> Klaus
>=20
> --- On Thu, 10/8/09, Jonathan wrote:
>=20
> From: Jonathan
> Subject: [MC4D] 4^4 parity alg
> To: 4D_Cubing@yahoogroups.com
> Date: Thursday, October 8, 2009, 10:58 AM
>=20
>=20
>=20
>=20
>=20
>=20
> =EF=BF=BD
>=20
>=20
>=20
>=20
>=20=20=20=20=20
> if anyone is curious on a algorithm that switches 2 pai=
rs of 3-colored pieces without messing up anything (even corners!),let me k=
now and ill respond with the solution..this algorithm can be useful on othe=
r sized cubes. its a manipulation of roice's old algorithms; ill use roice'=
s notation to explain it. this is the only parity i encountered in my solve=
(excluding the parities that can be solved with regular 4*4*4 algorithms). =
if anyone can show me the "Single 3-colour cubie flipped" in a picture or s=
omething that would be awsome or maby a description? lol=20=20
>=20
>=20
>=20
> cheers from Florida!
>




From: "Jonathan" <jonathan.mecias001@mymdc.net>
Date: Fri, 09 Oct 2009 02:42:10 -0000
Subject: Re: [MC4D] 4^4 parity alg



i will use ROICES NOTATION at(http://www.superliminal.com/cube/solution/pag=
es/cube.htm) also, i would like to thank roice because i used roice's techn=
iques and old algorithms.

-first: do the "first 3 color series.

-second: on the upper face(while holding down the number two key(2),right c=
lick on 11.

-third:do the reverse "first 3 color series"

-fourth:on the upper face(while holding down the number two key(2),left cli=
ck on 11.

the idea is simple. you can also manipulate roices other 3 piece orientatio=
n algorithms too. let me know if you have problems with that.

it should shuffle 3 3color pieces and nothing else. its 18 moves. you can a=
lso use variations of it by executing this algorithm on different faces(mig=
ht be helpful) for example: the upper and lower faces. let me know when you=
finish it because i'm curious on your solution simply because ive never us=
ed it!=20

cheers

--- In 4D_Cubing@yahoogroups.com, Klaus Weidinger wro=
te:
>
> Hi Jonathan,
>=20
> If you would find a similar algorithm for the 3^4 I would really apprecia=
te to hear of it, because I'm doing corners first and therefore the 3c-piec=
es are the last ones to solve
> for me.
>=20
> Have a nice twist,
> Klaus
>=20
> --- On Thu, 10/8/09, Jonathan wrote:
>=20
> From: Jonathan
> Subject: [MC4D] 4^4 parity alg
> To: 4D_Cubing@yahoogroups.com
> Date: Thursday, October 8, 2009, 10:58 AM
>=20
>=20
>=20
>=20
>=20
>=20
> =EF=BF=BD
>=20
>=20
>=20
>=20
>=20=20=20=20=20
> if anyone is curious on a algorithm that switches 2 pai=
rs of 3-colored pieces without messing up anything (even corners!),let me k=
now and ill respond with the solution..this algorithm can be useful on othe=
r sized cubes. its a manipulation of roice's old algorithms; ill use roice'=
s notation to explain it. this is the only parity i encountered in my solve=
(excluding the parities that can be solved with regular 4*4*4 algorithms). =
if anyone can show me the "Single 3-colour cubie flipped" in a picture or s=
omething that would be awsome or maby a description? lol=20=20
>=20
>=20
>=20
> cheers from Florida!
>




From: Klaus Weidinger <klaus.weidinger@yahoo.com>
Date: Fri, 9 Oct 2009 06:37:41 -0700 (PDT)
Subject: Re: [MC4D] 4^4 parity alg







=A0




=20=20=20=20
i will use ROICES NOTATION at(http://www.superlim inal.co=
m/ cube/solution/ pages/cube. htm) also, i would like to thank roice becaus=
e i used roice's techniques and old algorithms.



-first: do the "first 3 color series.



-second: on the upper face(while holding down the number two key(2),right c=
lick on 11.



-third:do the reverse "first 3 color series"



-fourth:on the upper face(while holding down the number two key(2),left cli=
ck on 11.



the idea is simple. you can also manipulate roices other 3 piece orientatio=
n algorithms too. let me know if you have problems with that.



it should shuffle 3 3color pieces and nothing else. its 18 moves. you can a=
lso use variations of it by executing this algorithm on different faces(mig=
ht be helpful) for example: the upper and lower faces. let me know when you=
finish it because i'm curious on your solution simply because ive never us=
ed it!=20



cheers



--- In 4D_Cubing@yahoogrou ps.com, Klaus Weidinger w=
rote:

>

> Hi Jonathan,

>=20

> If you would find a similar algorithm for the 3^4 I would really apprecia=
te to hear of it, because I'm doing corners first and therefore the 3c-piec=
es are the last ones to solve

> for me.

>=20

> Have a nice twist,

> Klaus

>=20

> --- On Thu, 10/8/09, Jonathan wrote:

>=20

> From: Jonathan

> Subject: [MC4D] 4^4 parity alg

> To: 4D_Cubing@yahoogrou ps.com

> Date: Thursday, October 8, 2009, 10:58 AM

>=20

>=20

>=20

>=20

>=20

>=20

> =EF=BF=BD

>=20

>=20

>=20

>=20

>=20=20=20=20=20

> if anyone is curious on a algorithm that switches 2 pai=
rs of 3-colored pieces without messing up anything (even corners!),let me k=
now and ill respond with the solution..this algorithm can be useful on othe=
r sized cubes. its a manipulation of roice's old algorithms; ill use roice'=
s notation to explain it. this is the only parity i encountered in my solve=
(excluding the parities that can be solved with regular 4*4*4 algorithms). =
if anyone can show me the "Single 3-colour cubie flipped" in a picture or s=
omething that would be awsome or maby a description? lol=20=20

>=20

>=20

>=20

> cheers from Florida!

>




=20

=20=20=20=20=20=20

=20=20=20=20
=20=20=20=20
=09
=09=20
=09
=09








=09


=09
=09


=20=20=20=20=20=20
--0-1201375489-1255095461=:53568
Content-Type: text/html; charset=iso-8859-1
Content-Transfer-Encoding: quoted-printable

top" style=3D"font: inherit;">Thanks for this sequence. I'm going to attemp=
t my second solve today and I'm going to give your sequence a try. However =
I already have some sequences for that purpose and the seem to be of equal =
length.

Btw: Is there anybody who knows a very good system to solve =
the 2^3 with as few turns as possible in quarter turn metric? I am currentl=
y using the Guimond method but I think it still uses too many turns.
>Have a nice twist,
Klaus
--- On Fri, 10/9/09, Jonathan <jon=
athan.mecias001@mymdc.net>
wrote:
-left: 2px solid rgb(16, 16, 255); margin-left: 5px; padding-left: 5px;">r>From: Jonathan <jonathan.mecias001@mymdc.net>
Subject: Re: [MC4D=
] 4^4 parity alg
To: 4D_Cubing@yahoogroups.com
Date: Friday, October =
9, 2009, 2:42 AM






 


i will use ROICES NOTATION at(et=3D"_blank" href=3D"http://www.superliminal.com/cube/solution/pages/cube.=
htm">http://www.superlim inal.com/ cube/solution/ pages/cube. htm
) also=
, i would like to thank roice because i used roice's techniques and old alg=
orithms.



-first: do the "first 3 color series.



-second: on the upper face(while holding down the number two key(2),right c=
lick on 11.



-third:do the reverse "first 3 color series"



-fourth:on the upper face(while holding down the number two key(2),left cli=
ck on 11.



the idea is simple. you can also manipulate roices other 3 piece orientatio=
n algorithms too. let me know if you have problems with that.



it should shuffle 3 3color pieces and nothing else. its 18 moves. you can a=
lso use variations of it by executing this algorithm on different faces(mig=
ht be helpful) for example: the upper and lower faces. let me know when you=
finish it because i'm curious on your solution simply because ive never us=
ed it!



cheers



--- In arget=3D"_blank" href=3D"/mc/compose?to=3D4D_Cubing%40yahoogroups.com">4D_C=
ubing@yahoogrou ps.com
, Klaus Weidinger <klaus.weidinger@ ...> wr=
ote:

>

> Hi Jonathan,

>

> If you would find a similar algorithm for the 3^4 I would really appre=
ciate to hear of it, because I'm doing corners first and therefore the 3c-p=
ieces are the last ones to solve

> for me.

>

> Have a nice twist,

> Klaus

>

> --- On Thu, 10/8/09, Jonathan <jonathan.mecias001 @...> wrote:r>
>

> From: Jonathan <jonathan.mecias001 @...>

> Subject: [MC4D] 4^4 parity alg

> To: target=3D"_blank" href=3D"/mc/compose?to=3D4D_Cubing%40yahoogroups.com">4D=
_Cubing@yahoogrou ps.com


> Date: Thursday, October 8, 2009, 10:58 AM

>

>

>

>

>

>

> =EF=BF=BD

>

>

>

>

>

> if anyone is curious on a algorithm that switches 2 =
pairs of 3-colored pieces without messing up anything (even corners!),let m=
e know and ill respond with the solution..this algorithm can be useful on o=
ther sized cubes. its a manipulation of roice's old algorithms; ill use roi=
ce's notation to explain it. this is the only parity i encountered in my so=
lve(excluding the parities that can be solved with regular 4*4*4 algorithms=
). if anyone can show me the "Single 3-colour cubie flipped" in a picture o=
r something that would be awsome or maby a description? lol

>

>

>

> cheers from Florida!

>




=20

=20=20


=09=20
=09





=20=20=20=20=20=20
--0-1201375489-1255095461=:53568--




From: Melinda Green <melinda@superliminal.com>
Date: Fri, 09 Oct 2009 11:24:04 -0700
Subject: Re: [MC4D] 4^4 parity alg



--------------020800040400000402020807
Content-Type: text/plain; charset=ISO-8859-1; format=flowed
Content-Transfer-Encoding: 7bit

I don't know but I did find it very interesting when I learned the other
day that the world record time for solving a 2^3 was set last year by
Erik Akkersdijk at just under one second
!! Wow.

-Melinda

Klaus Weidinger wrote:
>
>
> Thanks for this sequence. I'm going to attempt my second solve today
> and I'm going to give your sequence a try. However I already have some
> sequences for that purpose and the seem to be of equal length.
>
> Btw: Is there anybody who knows a very good system to solve the 2^3
> with as few turns as possible in quarter turn metric? I am currently
> using the Guimond method but I think it still uses too many turns.
>
> Have a nice twist,
> Klaus
>
> __

--------------020800040400000402020807
Content-Type: text/html; charset=ISO-8859-1
Content-Transfer-Encoding: 7bit







I don't know but I did find it very interesting when I learned the
other day that the world record time for solving a 2^3 was set last
year by Erik Akkersdijk at href="http://en.wikipedia.org/wiki/Pocket_Cube#Records">just under one
second!! Wow.



-Melinda



Klaus Weidinger wrote:

type="cite"> 






style="font-family: inherit; font-style: inherit; font-variant: inherit; font-weight: inherit; font-size: inherit; line-height: inherit; font-size-adjust: inherit; font-stretch: inherit;"
valign="top">Thanks for this sequence. I'm going to attempt my second
solve today and I'm going to give your sequence a try. However I
already have some sequences for that purpose and the seem to be of
equal length.



Btw: Is there anybody who knows a very good system to solve the 2^3
with as few turns as possible in quarter turn metric? I am currently
using the Guimond method but I think it still uses too many turns.



Have a nice twist,

Klaus







__





--------------020800040400000402020807--





Return to MagicCube4D main page
Return to the Superliminal home page